ML Aggarwal Class 8 Chapter 1 Rational Numbers Exercise 1.5

 Exercise 1.5

Question 1

Sol :
(i) $\frac{11}{4}=2.75$  





(ii) $4 \frac{3}{5}=\frac{23}{5}=4.6$  




(iii) $\frac{-9}{7}=-1 \frac{2}{7}$




(iv) $\frac{-2}{-5}=\frac{2}{5}=0.4$





Question 2

Sol :
(i)  $A=\frac{3}{7}$

$B=\frac{7}{7}=1$

$C=\frac{8}{7}$

$D=\frac{12}{7}$

$E=\frac{13}{7}$       
                    

(ii) $\quad P=\frac{-3}{8}$                                                        
 
$Q=\frac{-4}{8}=-\frac{1}{2}$

$R=\frac{-7}{8}$

$S=\frac{-11}{8}$

$T=\frac{12}{8}=\frac{-3}{2}$

Question 3

Sol :
$\frac{-3}{7} \quad \frac{-3}{10}$ $\frac{-5} {20}\frac{-2}{10}$ $\frac{-3}{20} \frac{-1}{10}\frac{-1}{20}$ $0 \frac{1}{20} \frac{1}{10} \frac{3}{20} \frac{2}{10} \frac{5}{20} \frac{3}{10}$ 

$\begin{array}{ccccccc}\frac{7}{20} & \frac{4}{10} & \frac{9}{20} & \frac{5}{10} & \frac{11}{20} & \frac{6}{10} & \frac{2}{3}\end{array}$

Question 4

Sol :




Question 5

Sol :




Question 6

Sol :
1,2,3,4,5,6,7,8,9,10

Question 7

Sol :
-5,-6,-7,-8,-9

Question 8

Sol :
$-\frac{7}{3}$ (Numerator is greater then denominator (numerically)

$-\frac{7}{3}<-1 ;-\frac{5}{11}, \frac{-1}{2}, \frac{-4}{9}>-1 .$

$\therefore \quad \frac{-7}{3}$ is different among all rational numbers

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