ML AGGARWAL CLASS 8 Chapter 14 Constructions of Quadrilaterals Exercise 14.2
Exercise 14.2
Question 1
Sol :
1. Draw AB=5 cm
2. Draw $\angle B=120^{\circ}$ line and Cut it ar $\overline{B C}=3.2 \mathrm{cm}$, mark point ' c '
3.Draw $\angle A=\left(180^{\circ}-120^{\circ}\right)=60^{\circ}$ at Cut it at $\overline{AD}=$ 3.2cm , Mark point 'D'
4.Now join $\overline{D C}$, required quadrilateral ABCD formed.
Question 2
Sol :
1. Draw AB=4.8 cm line
2 Draw B C =4cm Arc formed 'B'
3. Draw AD=BC=4 in Arc form A
4.Draw BD = 5.4cm are form B, intersection point 'D'
5.Join $\overline{ AD}$ and draw BC line parallel to AD intersection point is 'C'
6.Join $\overline{D C}, \overline{B C}$ now required quadrilateral is formed.
Question 3
Sol :
1.Draw BC = 4.5 cm
$B O=\frac{1}{2}(B D)=\frac{1}{2}(4)$=2 cm
$C O=\frac{1}{2}(A C)=\frac{1}{2}(56)=2.8 \mathrm{cm}$
$'O^{\prime}$ is formed.
2. Extend BO Such that BD=4 cm
3.Extend CO Such that AC= 5.6 cm
4. Now required parallelogram ABCD is formed
Question 4
Sol :
1. Draw $A O=\frac{1}{2}(A C)$=3cm and produce AO to C such thus OC=OA
2. AO Construct $\angle A O P=45^{\circ}$
3.From OP, cut OB = 2.5cm , produced OB to D such thus OB = OD
4. Join $\overline{A D}, \overline{A B}, D \overline {C}, \overline{C D}$ ABCD parallelogram formed.
Question 5
Sol :
1.Draw AB= 5.6cm
2.Draw $\angle B=90$ and BC = 4cm
3.Draw $\angle A=90$ and AD=BC=4C
4. Join $\overline$ DC , now rectangle ABCD is formed
Question 6
Sol :
Steps.
1. Draw AB=5 cm
Draw AO=BO=3.4 cm
2. Extend AO to C such that AC=6.8cm
Extend BO to D Such them BD=6.8 cm
3. Join $\overline{A D}, \overline{D C}, \overline{B C}$, Now rectangle ABCD is formed.
Question 7
Sol :
1. Draw AB=4 cm
2. Draw $\angle BAC=90$ \& $\angle B 290^{\circ}$,
3. join $\overline{D C}$, A D, required rectangle ABCD is formed.
Question 8
Sol :
Steps.
1. AO=9.3 cm extend to C
Such that AO = OB
2. $\angle A O B=120^{\circ}$ and Draw BO=3.3 cm and external to D such then BO =OD
3. Join $\overline{A B}, \overline{B C}, \overline{C D}, \overline{A D}$, Now required rectangle ABCD is formed
Question 9
Steps.
1.Draw AB = 5cm
2. At 'A' construct $\angle B A P=45^{\circ}$
3. From AP, cut off AD = 5cm
4.With B as centre and radius 5cm draw an arc
5.With D as centre and radius 5cm draw are meet radius arc at C
6. Join BC and CD Then ABCD a required rhombus
Question 10
Steps.
1. Draw AB=4.5 cm
2. A as centre ,with 4.5cm radius draw arc
3. B as centre , with 5cm radius draw arc which meet previous arc at 'D'
4. With DC as centre with 4.5cm radius draw arcs they meet at 'C'
5. Join $\overlineAD, \overline\overline{D C}, \overline{B C}$, then A B C D is required rhombus
Question 11
Sol :
1. Draw AC=6.8 cm
2. Draw PQ, which perpendicular bisector of AC
3.Cut PQ such then OB= OD =2.6cm
4.Join $\overline{A B}, \quad \overline{B C},\overline{C D}, \overline{A D}$
Now ABCD is required rhombus.
Question 12
Sol :
1. Draw AB=4.3 cm
2. $\angle A=90^{\circ}$ 'A' as centre, 4.4 cm radius draw arc , both meet at 'D'
3. Repeat the same at 'B' 'C' is Formed
4. Join AD, DC, BC , Now ABCD is required Square.
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