ML Aggarwal Solution Class 10 Chapter 2 Banking Test

Test

Question 1

Mr. Dhruv deposits Rs 600 per month in a recurring deposit account for 5 years at the rate of 10% per annum (simple interest). Find the amount he will receive at the time of maturity.

Sol :

Deposit per month = Rs 600

Rate of interest = 10% p.a.

Period (n) = 5 years 60 months.

Total principal for one month

=600×n(n+1)2=600×60(60+1)2

=600×60×612=1098000

Interest =PRT100 =1098000×10×1100×12=9150

∴Amount of maturity =600×60+9+50

=₹ 36000+₹ 9150=₹ 45150


Question 2

Ankita started paying Rs 400 per month in a 3 years recurring deposit. After six months her brother Anshul started paying Rs 500 per month in a 212 years recurring deposit. The bank paid 10% p.a. simple interest for both. At maturity who will get more money and by how much?

Sol :

In case of Ankita,

Deposit per month = Rs 400

Period (n) = 3 years = 36 months

Rate of interest = 10%

Total principal for one month

=400×n(n+1)2=400×36(36+1)2

=400×36×372=266400

Interest =PRT100 =266400×10×1100×12=2220

∴Amount of maturity =₹ 400 \times 36+₹ 2220

=₹ 14400+₹ 2220=₹ 16620

In case of Anshul, 

Deposit p.m.=₹ 500

Rate of interest =10 %

Period (n)=212 years =30 months

∴Total principal for one month

=500×n(n+1)2=500×30(30+1)2

=500×30×312=232500

Interest =232500×10×1100×12=1937.50

Amount of maturity =₹ 500 × 30+₹ 1937.50

=₹ 15000+₹ 1937.50=₹ 16937.50

At maturity Anshul will get more amount

Difference =₹ 16937.50-₹ 16620.00

=₹ 317.50


Question 3

Shilpa has a 4 year recurring deposit account in Bank of Maharashtra and deposits Rs 800 per month. If she gets Rs 48200 at the time of maturity, find

(i) the rate of simple interest,

(ii) the total interest earned by Shilpa

Sol :

Deposit per month (P) = Rs 800

Amount of maturity = Rs 48200

Period (n)=4 years =48 months

Let rate of interest be R % p.a.

Total principal for one month

=P(n)(n+1)2=800×48×(48+1)2 =800×48×492=940800

Total deposit =₹ 800 \times 48=₹ 38400

∴Interest earned =₹ 48200-₹ 38400=₹ 9800

(i) Rate of interest = S.I. ×100P×T

=9800×100×12940800×1=12.5%

(ii) Total interest earned by Shilpa =9800


Question 4

Mr. Chaturvedi has a recurring deposit account in Grindlay’s Bank for 412 years at 11% p.a. (simple interest). If he gets Rs 101418.75 at the time of maturity, find the monthly instalment.

Sol :

Let each monthly instalment = Rs x

Rate of interest = 11 %

Period (n)=412 years or 54 months,

Total principal for one month

=x×n(n+1)2=x×54(54+1)2

=x×54×552=1485x

Interest =1485x×11×1100×12=136125x

∴Total amount of maturity =54x+136125x

=67.6125x

∴67.6125 x=101418.75

x=10141875676125=1500

∴Deposit per month =₹ 1500


Question 5

Rajiv Bhardwaj has a recurring deposit account in a bank of Rs 600 per month. If the bank pays simple interest of 7% p.a. and he gets Rs 15450 as maturity amount, find the total time for which the account was held.

Sol :

Deposit during the month (P) = Rs 600

Rate of interest = 7% p.a.

Amount of maturity = Rs 15450

Let time = n months

∴Total principal =P(n)(n+1)2

=600×n(n+1)2=600(n2+n)2=300(n2+n)

∴Interest = PRT 100=300(n2+n)×7×1100×12

=74(n2+n)

600n+74(n2+n)=15450

⇒2400n+7n2+7n=61800

⇒7n2+2407 n-61800=0

⇒7n2-168 n+2575 n-61800=0

⇒7 n(n-24)+2575(n-24)=0

⇒(n-24)(7 n+2575)=0

Either n-24=0, then n=24

or 7 n+2575=0, then

7n=2575n=25757

Which is not possible being negative.

∴n=24

∴Period=24 months or 2 years

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