ML AGGARWAL CLASS 8 Chapter 19 Data Handiling Exercise 19.2
Exercise 19.2
Question 1
Sol :
To represent given data in pie chart , we have to find angles
Total animals = 40+ 10+30+ 15+25= 120
Animals no.of animals Angle
Deer 40 40120×360=120∘
Tiger 10 10120×360=30∘
Elephant 30 30120×360=90∘
Reptiles 25 25120×360=75∘
Giraffe 15 15120×360=45∘
Question 2
Sol :
To represent given data in pie chat we have to find angles
Total expenditure = 12500+5000+7500+10000+5000+10000=50,000
Item Expenditure Angle
1.Food 12500 1250050000×360=90
2.House rent 5000 500050000×360=36∘
3.Education 7500 750050000×360=54∘
4.Savings 10000 1000050000×360=72∘
5.Health 5000 500050000×360=36∘
6. Others 10000 1000050000×360=72∘
Question 3
Sol :
To represent given data to pie chart we have to find angles
Total = 25+20+20+10+15+10=100%
Item Expenditure Angle
Paper cost- 25% 25100×360=90∘
Printing cost 20% 20100×360=72∘
Binding 20% 20100×360=72∘
Royalty 10% 10100×360=36∘
Transportation cost 15% 15100×360=54∘
Promotion cost 10% 10100×360=36∘
Question 4
Sol :
To represent above data in pie chart we have to find angles
Total no. of students = 400+300+500+250+350=1800
Stream No. of Students Angle
Science 400 4001800×360∘=80∘
Arts 300 3001800×360=60∘
Commerce 500 5001800×360∘=100∘
Law 250 2501800×360∘=50∘
Management 350 3501800×360∘=70∘
Question 5
Sol :
(i) 90∘360×100=14×100=25 %
(ii) Hockey - 75∘
Tennis - 50'
Directer =75−50=25∘
25∘360×100=6.94 %
(iii) Badminton -- 60
60∘360×100=16.67t.
Total Amount =18000000
Amount spend on Badminton =16.67100×18000000
=30,00000
(iv)Hockey--- 75∘
Cricket ---90'
h+ c= 75+90 = 165'
Both H and c = 165∘360×100 =45.83%.
Total amount 2,40,00,000
Amount spent on both hockey and cricket = 45.83100×2,40,00,000
= 11,000,000
Question 6
Sol :
(i) Angle of class viii = 85∘
% of class viii = 85360×100=28.611%
No. of students enrolled in class viii ==28.61100×1440
=340
(ii) Angle of class ix = 75∘
Angle of class x = 50∘
Difference = 75−50=25∘
% of Difference = 25360×100=6.94%
No. of Students enrolled more in class ix Then class x
is = 6.94100×1440=100
(iii) Angle of class viii = 85∘
Angle of class vii = 70∘
Sum = 85+70=155∘
% of sum = 155360×100=43.05%
Total Students in class viii and class vii =43.05100×1440
=620
(iv) Angle of class vi = 80∘
Angle of class x = 50∘
% of class vi = 80360×100=22.22%
% of class x = 50360×100=13.88%
No. of Students enrolled in class vi = 22.22100×1440
= 320
No. of Students enrolled in class x = 13.88100×1440
= 200
Ratio of students enrolled in Class vi to Class X = 320: 200
= 8:5
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