ML AGGARWAL CLASS 8 Chapter 19 Data Handiling Exercise 19.2

 Exercise 19.2

Question 1

Sol :

To represent given data in pie chart , we have to find angles 

Total animals = 40+ 10+30+ 15+25= 120


Animals          no.of animals             Angle

Deer                  40                          $\frac{40}{120} \times 360=120^{\circ}$

Tiger                 10                          $\frac{10}{120} \times 360=30^{\circ}$

Elephant            30                         $\frac{30}{120} \times 360=90^{\circ}$

Reptiles             25                         $\frac{25}{120} \times 360=75^{\circ}$

Giraffe               15                         $\frac{15}{120} \times 360=45^{\circ}$















Question 2

Sol :

To represent given data in pie chat we have to find angles

Total expenditure = 12500+5000+7500+10000+5000+10000=50,000

    Item                Expenditure                   Angle 

1.Food                 12500                         $\frac{12500}{50000} \times 360=90$
 
2.House rent        5000                           $\frac{5000}{50000} \times 360=36^{\circ}$

3.Education          7500                          $\frac{7500}{50000} \times 360=54^{\circ}$

4.Savings             10000                        $\frac{10000}{50000} \times 360=72^{\circ}$

5.Health                5000                         $\frac{5000}{50000} \times 360=36^{\circ}$ 

6. Others               10000                       $\frac{10000}{50000} \times 360=72^{\circ}$














Question 3

Sol :

To represent given data to pie chart we have to find angles 

Total = 25+20+20+10+15+10=100%


    Item                  Expenditure                        Angle 

Paper cost-                 25%                             $\frac{25}{100} \times 360=90^{\circ}$  

Printing cost               20%                           $\frac{20}{100} \times 360=72^{\circ}$

Binding                       20%                          $\frac{20}{100} \times 360=72^{\circ}$

Royalty                      10%                          $\frac{10}{100} \times 360=36^{\circ}$

Transportation cost      15%                          $\frac{15}{100} \times 360=54^{\circ}$
 
Promotion cost           10%                          $\frac{10}{100} \times 360=36^{\circ}$

















Question 4

Sol :

To represent above data in pie chart we have to find angles

Total no. of students = 400+300+500+250+350=1800


Stream                 No. of Students                  Angle

Science                 400                                   $\frac{400}{1800} \times 360^{\circ}=80^{\circ}$

Arts                       300                                  $\frac{300}{1800} \times 360=60^{\circ}$

Commerce           500                                   $\frac{500}{1800} \times 360^{\circ}=100^{\circ}$

Law                      250                                  $\frac{250}{1800} \times 360^{\circ}=50^{\circ}$

Management          350                                 $\frac{350}{1800} \times 360^{\circ}=70^{\circ}$
















Question 5

Sol :

(i) $\frac{90^{\circ}}{360} \times 100=\frac{1}{4} \times 100=25$ %


(ii) Hockey - $75^{\circ}$

Tennis - 50'

Directer $=75-50=25^{\circ}$

$\frac{25^{\circ}}{360} \times 100=6.94$ %


(iii) Badminton -- 60

$\frac{60^{\circ}}{360} \times 100=16.67 t .$

Total Amount $=18000000$

Amount spend on Badminton $=\frac{16.67}{100} \times 18000000$

=30,00000


(iv)Hockey--- $75^{\circ}$

Cricket ---90'

h+ c= 75+90 = 165'

Both H and c = $\frac{165^{\circ}}{360} \times 100$ $=45.83 \%$.

Total amount 2,40,00,000

Amount spent on both hockey and cricket = $\frac{45.83}{100} \times 2,40,00,000$

 = 11,000,000



Question 6

Sol :

(i) Angle of class viii = $85^{\circ}$

% of class viii = $\frac{85}{360} \times 100=28.611 \%$

No. of students enrolled in class viii =$=\frac{28.61}{100} \times 1440$

$=340$


(ii) Angle of class ix = $75^{\circ}$

Angle of class x = $50^{\circ}$

Difference = $75-50=25^{\circ}$

% of Difference = $\frac{25}{360} \times 100=6.94$%

No. of Students enrolled more in class ix Then class x 

is = $\frac{6.94}{100} \times 1440=100$


(iii) Angle of class viii = $85^{\circ}$

Angle of class vii = $70^{\circ}$

Sum = $85+70=155^{\circ}$

% of sum = $\frac{155}{360} \times 100=43.05 \%$

Total Students in class viii and class vii $=\frac{43.05}{100} \times 1440$

$=620$


(iv) Angle of class vi = $80^{\circ}$

Angle of class x = $50^{\circ}$

% of class vi = $\frac{80}{360} \times 100=22.22$%

% of class x = $\frac{50}{360} \times 100=13.88 \%$

No. of Students enrolled in class vi = $\frac{22.22}{100} \times 1440$

= 320 

No. of Students enrolled in class x = $\frac{13.88}{100} \times 1440$

= 200

Ratio of students enrolled in Class vi to Class X =  320: 200

= 8:5

Location: Lakhandur - Arjuni Rd, Maharashtra 441803, India

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