ML AGGARWAL CLASS 8 Chapter 19 Data Handiling Exercise 19.3
Exercise 19.3
Question 1
Sol :
(i) A, A, A, B, C, D
(ii)W , R, B, G, Y
Question 2
Sol :
(i) Total No. of Outcomes = {1,2,3,4,5,6}=6
Favorable Outcomes = {2,4,6}=3
Probability = no.of favorable outcomes Total no.of outcomes
36=1/2
(ii) Total No. of Outcomes = {1,2,3,4,5,6}=6
Favorable Outcomes= {3,6}=2
Probability = no.of favorable outcomes Total no.of outcomes
=26
=13
(iii) No. of multiple of '3' = {1,2,4,5}= 4
Probability = 46=23
Question 3
Sol :
(i) Total Outcomes = {TT,TH,HT,HH}=4
Getting two tail = {T,T } = 1
Probability =14
(ii) At least One tail = {TH, HT, TT}= 3
Probability = no.of favorable outcomes Total no.of outcomes
=34
(iii) No. tail = {H,H }= 1
Probability = 14
Question 4
Sol :
Total outcomes = {TTT, TTH , THT , HTT, THH, HHT,HTH, HHH}= 8
(i) At least two heads
Favorable outcomes = {TTT,TTH , THT, HTT} = 4
Probability =48=12
(ii) At least on tail
Favorable Outcomes = {TTT, TTH, THT, HTTT, THH, HHT,HTH}= 7
Probability = 78
(iii) At most one tail
Favorable Outcomes = {HHH,THH, HTH,HHT}= 4
Probability =48=12
Question 5
Sol :
When two dice rolled simultanilouly
Total no. of outcomes =36
(i) The sum as 7
Favorable Outcomes = {(11,6),(2,5),(3,4),(4,3),(5,2),(6,11)}
Probability =636=16
(ii) The sum as 3 or 4
Sum '3' = {(1,2),(2,1)}= 2
Sum '4' = {(1,3),(2,2),(3,1)}=3
Total = 2+3= 5
∴ Favorable Outcomes = 5
Probability = 536
(iii) Prime number on both dice
Favorable Outcomes = {(2,2),(2,3),(2,5),(3,2),(3,3),(3,5),(5,2),(5,3),(5,5)}=9
probability =936=14
Question 6
Sol :
Total Screws = 60
Rusted Screws= 600×110=60
(i) A rusted Screw
No. of favorable outcomes = 60
Probability=60600=110=0.1
(ii) Not a Rusted Screw
No of favorable outcomes = 600-60 = 540
Probability = 54060=0.9
Question 7
Sol :
TRIANGLE
Vowels ----{I, A, E }= 3
Total letters = 8
Probability = no.of vowels total no. of letter
=38
Question 8
Sol :
Bag = {5 Red, 6 black, 4 white } = 15 Balls
(i) Getting white
No. of favorable outcomes = 4
probability =415
(ii) Not black
Mean either red or white
No. of favorable outcomes = 5+ 4= 9
probability=915=35
(iii) Red or black
No. of favorable Outcomes = 5+ 6= 11
Probability 4=1115
Question 9
Sol :
Total Cards = 17 = {1,2,3,4,5,6.............10,11,12,13,14,15,16,17}
(i) odd
No. of favorable Outcomes = 9
Probability =917
(ii) Even
No. of favorable outcomes = 8
Probability 817
(iii) Prime
No. f favorable Outcomes {2,3,5,9,11,13,17}= 7
probability =717
(iv) divisible by 3
No of favorable outcomes = {3,6,9,12,15}=5
Probability =517
(v) Divisible by 2 and 3 both
No.of Favorable Outcomes = {6,12}=2
Probability =217
Question 10
Sol :
Total Cards = 52
(i) An ace
No. of favorable Outcomes = 4
probability =452=113
(ii) A red card
No.of favorable Outcomes = 26
Probability =2652=12
(iii) Neither a king nor a queen
No. of favorable outcome = 56−(4×2)=56−8=44
Probability = 4452
=1113
(iv) A Red face card
No.of favorable outcome= 3×2=6\
Probability =652=326
(v) A card of spade or an ace
No. of spades =n(s)=13
No.of Ace = n(A) = 4
No.of Ace or spade = n(s∧A)=1
∴n(S∪A)=n(s)+n(A)−n(S∧A)=13+4−1
n(S∪A)=16
No.of favorable outcomes = 16
Probabilily =1654=413
(vi) Non face card of red colour
No.of favorable outcomes = 26−(3×2)=20
Probability =2054
513
Question 11
Sol :
Total tickets =5+955=1000
No.of favorable outcomes = 5
Probability = 51000
=1200
∴ Probability that the person wins lottery is 1200
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