ML AGGARWAL CLASS 8 Chapter 19 Data Handiling Exercise 19.3

  Exercise 19.3

Question 1

Sol :

(i) A, A, A, B, C, D 

(ii)W , R, B, G, Y 


Question 2

Sol :

(i) Total No. of Outcomes = {1,2,3,4,5,6}=6

Favorable Outcomes = {2,4,6}=3

Probability = no.of  favorable outcomes  Total no.of outcomes 

36=1/2


(ii)  Total No. of Outcomes = {1,2,3,4,5,6}=6

Favorable Outcomes= {3,6}=2

Probability = no.of  favorable outcomes  Total no.of outcomes 

=26

=13


(iii) No. of multiple of '3' = {1,2,4,5}= 4

Probability = 46=23



Question 3

Sol :

(i) Total Outcomes = {TT,TH,HT,HH}=4

Getting two tail = {T,T } = 1

Probability =14


(ii) At least One tail = {TH, HT, TT}= 3

Probability = no.of  favorable outcomes  Total no.of outcomes 

=34


(iii) No. tail = {H,H }= 1

Probability = 14



Question 4

Sol :

Total outcomes = {TTT, TTH , THT , HTT, THH, HHT,HTH, HHH}= 8

(i) At least two heads 

Favorable outcomes = {TTT,TTH , THT, HTT} = 4

Probability =48=12


(ii) At least on tail 

Favorable Outcomes = {TTT, TTH, THT, HTTT, THH, HHT,HTH}= 7

Probability = 78


(iii) At most one tail

Favorable Outcomes = {HHH,THH, HTH,HHT}= 4

Probability =48=12


Question 5

Sol :

When two dice rolled simultanilouly 

Total no. of outcomes =36

(i) The sum as 7 

Favorable Outcomes = {(11,6),(2,5),(3,4),(4,3),(5,2),(6,11)}

Probability =636=16


(ii) The sum as 3 or 4

Sum '3' = {(1,2),(2,1)}= 2

Sum '4' = {(1,3),(2,2),(3,1)}=3

Total = 2+3= 5

∴ Favorable Outcomes = 5

Probability = 536



(iii) Prime number on both dice 

Favorable Outcomes = {(2,2),(2,3),(2,5),(3,2),(3,3),(3,5),(5,2),(5,3),(5,5)}=9

probability =936=14



Question 6

Sol :

Total Screws = 60 

Rusted Screws= 600×110=60


(i) A rusted Screw 

No. of favorable outcomes = 60

Probability=60600=110=0.1

(ii) Not a Rusted Screw 

No of favorable outcomes = 600-60 = 540

Probability = 54060=0.9



Question 7

Sol :

TRIANGLE 

Vowels ----{I, A, E }= 3

Total letters = 8

Probability =  no.of vowels  total no. of letter

=38



Question 8

Sol :

Bag = {5 Red, 6 black, 4 white } = 15 Balls 

(i) Getting white 

No. of favorable outcomes = 4

probability  =415


(ii) Not black 

Mean either red or white 

No. of favorable outcomes = 5+ 4= 9

probability=915=35


(iii) Red or black 

No. of favorable Outcomes = 5+ 6= 11

Probability 4=1115



Question 9

Sol :

Total Cards = 17 = {1,2,3,4,5,6.............10,11,12,13,14,15,16,17}

(i) odd

No. of favorable Outcomes = 9

Probability =917


(ii) Even 

No. of favorable outcomes = 8 

Probability 817


(iii) Prime 

No. f favorable Outcomes {2,3,5,9,11,13,17}= 7

probability =717


(iv) divisible by 3

No of favorable outcomes = {3,6,9,12,15}=5

Probability =517


(v) Divisible by 2 and 3 both

No.of Favorable Outcomes = {6,12}=2

Probability =217


Question 10

Sol :

Total Cards = 52


(i) An ace 

No. of favorable Outcomes = 4

 probability =452=113


(ii) A red card

No.of favorable Outcomes = 26

 Probability =2652=12


(iii) Neither a king nor a queen 

No. of favorable outcome = 56(4×2)=568=44

Probability = 4452

=1113


(iv) A Red face card 

 No.of favorable outcome= 3×2=6\

 Probability =652=326


(v) A card of spade or an ace 

No. of spades =n(s)=13

No.of Ace = n(A) = 4

No.of Ace or spade = n(sA)=1

n(SA)=n(s)+n(A)n(SA)=13+41

n(SA)=16

No.of favorable outcomes = 16

 Probabilily =1654=413


(vi) Non face card of red colour

No.of favorable outcomes = 26(3×2)=20

Probability =2054

513



Question 11

Sol :

Total tickets =5+955=1000

No.of favorable outcomes = 5

Probability = 51000

=1200

∴ Probability that the person wins lottery is 1200

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