ML AGGARWAL CLASS 8 CHAPTER 6 Operation on Sets Venn Diagrams Exercise 6.2

Exercise 6.2

Question 1

Sol :

(i) A={0,5,7,8,9,11}

(ii) B={2,5,6,8}

(iii) ξ={0,1,2,4,5,6,7,8,9,11,12}

(iv) A={1,2,4,12}

(v) B={0,1,4,7,9,11,12}

(vi) AB={0,2,5,6,7,8,9,11}

(vii) AB={5,8}

(viii) (AB)={1,4,12}

(ix) (AB)={0,1,2,4,6,7,9,11,12}


Question 2

Sol :

(i) P={a, b, d, f, g, h, i}

(ii) Q={b, d, e}

(iii) ξ={a,b,c,d,e,f,q,h,i}

(iv) p={c,j}

(v) Q={a,c,f,g,h,i,j}

(vii) pQ={b,d,e}

(viii) (pQ)={c,j}

(ix) (PQ)={a,C,f,g,h,1,j}

Question 3

Sol :
(i) ξ={0,1,2,3,4,5,6,7,8,9,10,11,12}

(ii) AB={0,5,8}

(iii) ABC={0,5}

(iv) C={2,7,8,9,10,11,12}

(v) AC=AC={8,10}

(vi) BC=BC={7,8,11}

(vii) CB=CB={3,4,6}

(viii) (AB)={2,4,6,9,12)

(ix) (ABC)={2,9,12}



Question 4

Sol :
(i) $\begin{aligned} A &=\{x \mid x \in N, x=2 n, n \leq 5\} ; B=\{x \mid x \in W, x=4 n, n<5\} \\ A &=\{2,4,6,8,10\} \quad B=\{4,8,12,16\} \end{aligned}$









(ii) A={ prime factors of 42)B={ prime factors of 60}A={2,3,7}B={2,3,5}







(iii) P={xxW,x<10}Q{ prime factor of 210}P={0,1,2,3,4,5,6,7,8,9}Q,{2,3,7,5}







Question 5

Sol :

$n(A)=22 \quad n(B)=18 \quad n(A \cap B)=5$








(i) n(AB)=17+5+13=35

(ii) n(AB)=n(A)n(AB)=175=12

(iii) n(BA)=η(B)n(AB)=135=8


Question 6

Sol :

n(A)=25n(B)=16,n(AB)=6,n((AB))=5










(i) n(AB)=19+6+10=35

(ii) n(ξ)=n(AB)+n((AB))=35+5=40

(iii) n(AB)=η(A)n(AB)=256=19

(iv) n(BA)=n(B)n(AB)=166=10


Question 7

Sol :

n(ξ)=25n(A)=7n(B)=10BCA











n(A)=n(ξ)n(A)=257=18

n(AB)=n(A)n(AB)=1810=8

Cardinal number of set A-B is 8

Question 8

Sol :











(i) No of boys who play at least one of the two games

=20+12+5=37

(ii) Neither cricket nor fast ball 

n((AB))= Total student n(AB)=5037=13


Question 9

Sol :










(i) Both Orange and Banana.

n(AB) = no of students who like both orange and banana 
                        =no of student who like orange - no of students who like orange but not banana

= 32- 26

= 6 

(ii) n(B)=?n(AB)n(A)+n(B)n(AB)n(B)=4032+6=4632=14

number of student who like only banana =14-6=8


Question 10

Sol :











n(AB)=x

n(AB)=n(A)+n(B)n(AB)

60=45+28-x

x=73-60

x=13

∴ no of people who speak both Bengali and English are 13

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