ML AGGARWAL CLASS 8 CHAPTER 7 Percentage Exercise 7.2

    Exercise 7.2

Question 1

Sol :

(i) C.P 400  S.P = 468

  S.P > c.p , profit = s.p-C.p =468400=68

profit percentage = =( profit cp×100)%

=(68400×100)%

=17


(ii) C.P = 13600  , S.P = 12104

As C.p > S. P  Loss =c.psp=13,60012,10y=1496

loss percentage  
=( Loss c.p×100)%=(149613600×100)%=11% 



Question 2

Sol :


Given SP=1636.25, gain =96.25

As Gain=SpCp

⇒ CP=SpGain=1636.2596.25=1540.

⇒ Gain percentage
 =(Gaincp×100)%=(96251540×100)%=6.25%


Question 3

Sol :

Given 

         S.P = 770  LOSS = 110

As loss = c.p - s.p 

c.p = loss + s.p 

= 110 + 700

⇒ 880

Loss percentage 
=( Loss c.p×100)%=(110880×100)%=12.5%



Question 4

Sol :

c.p of 1 dozen eggs =9.60

c.p of 25 dozen eggs =(25×9.6)=240

Total no of eggs =25×12=300 eggs

Out of 300 eggs, 30 eggs were broken

So the remaining no of eggs were 300 - 30 = 270 eggs 

Given  

S.P of each egg = Rs 1 

S. of 270 eggs =270×1=270

As Sp>c.p, he always gets profit on given

So the gain percentage = (gaincp×100)%

Gain = S.P - C.P 

⇒ 270 - 240 = 30 

Gain percentage = (30240×100)%

=12.5%


Question 5

Sol :

C.P of an article
=20,000+1400 (repairs) =21,400

profit percentage =20 %

 profit  c.p ×100=20
Profit x×100=20×21,400

(SPCP)=20×214

S.P-21,400=4280

Sp=21,400+4280sp=25680

Selling price of an article = 25,680


Question 6

Sol :
C.P of bicycles includes

(i) 200 bicycles at 1200. per bicycle =(200×1200)=240000

(ii) 301- per bicycle on transportation =200×30=6000

(iii) 40001- on advertising =4000

Total cost price of bicycles =2,40,000+6000+4000

S.P of 200 bicycles =200×1350

As SP>CP, there is always a gain

So Gain =SP-CP

=2,70,0002,50,000=20,000

=Gainc.p×100

=20,0002,50000×100

=8 %



Question 7

Sol :
Let S.P be ₹ x ,

then CP 90 % of x 

=910x

 Profit =spcp=x9x10=x10

 profit percentage =( Profit  c. p×100)%=((x/10)(9×10)×100)%=1009%=11.11%



Question 8

Sol :

(i) CP of 4 note boots =35

then c.s of 1 note book =354=8.75 

Sp of 5 note books =58

then sp of 1 notebook =585=11.6%

As. SP>CP there is always a gain

Gain = SP-CP = 11.6 - 8.75

= 2.85

Gain percentage 
=GainCp×100=2.858.25×100=32.57%

(ii) Number of notebooks to be sold =  total profit  profit on one notebooks 

=1712.85

=60 

Question 9

Sol :

Cost price of 3 bananas = Rs 1 

The c .p of 1 banana = Rs 13=0.33

S.p of 4 bananas = Rs 1

Then S.P of 1 banana = Rs 14=0.25

As C.P>SP, These is always a loss.

 Loss =Cpsp=1314

=112

 Loss percentage = Loss c.p×100%=(1/12)(1/3)×100%=1004%=25%


Question 10

Sol :
Given S.P of 5 pens = C.P of 7 pens

let cost price of one pen be x then 

C.P of  7 pens = Rs 7x

It is given 

S.P of 5 pens = c.p of 7 pens 

S.P of 5 pens = rs 7x 

S.P of one pen = 7x5

As  SP>C.P there is a profit

 profit =Spcp=7x5x=2x5

∴  Profit percentage = profit Cp×100%=(2x/5)x×100%=2005%=40%

Question 11

Sol :

(i) CP=2360, profit =8 %

As. Profit percentage = profit C.p×100

 profit ×100=8×2360 profit =8×2360100S.PCp=188.8Sp=2360+1888SP=2548.8


(ii) CP=380 ; loss=7.5 %

Loss percentage = loss  C.P ×100

Loss =7.5×380100

cps.p=28.5sp=38028.5sp=351.5



Question 12

Sol :
CP of dozen egg =18

then CP of 1 egg=1812=21.5

Profit =50 %

SPCPC.P×100=50

SP-CP=9

SP=18+9

SP=27

S.P of 1 egg  =2712=22.25


Question 13

Sol :
Let the no of wrist watches are x 

cost of x wrist watches Rs 60,000

C.P one third of wrist watches will worth 20,000

(i) As we know 13rd are sold at a 30% profit

Sp=[1+P100] of C.P=[1+30100]×20,000=130100×20,000=26,000


(ii) SP=[1+p100] of CP [ 
As 13rd are sold at 20 % gain]

=[1+20100]×20,000

=120100×20,000
=24,000


(iii) SP=(1l100) of c.p [Remaining are sold at a 5 % Less ]

=[15100]×20,000

=95100×20,000

=19,000

Total cost price = ₹ 60,000

 Selling price =[26,000+24,000+19,000]=69000

As SP>CP these is always a profit

Gain=SpCp=69,00060,000=9,000

Gain percentage
==Gaincp×100%=9,00069,000×100%=15%

Question 14

Sol :
C.P of a Laptop = 40,000

C.P of a mobile phone =  24,000

Total CP of whole Transaction =40,000+24,000
=64,000

As shopkeeper made a profit of 8 % on laptop

 So. sp=(1+p100) of cp=[1+8100]×40,000=108100×40,000=43,200

Also, he made a loss of 12 % on mobile phone

SP=[1l100] of CP=[112100]×24,000=88100×24,000=21,120

Total S.P on whole Transaction =43,200+21,120
=64,320 .

As, SP>CP there is always a gain

 Gain =Spcp=64,32064,000=320 Gain percentage =GainCip×100

=0.5 %

Question 15

Sol :
C.P of 40 chairs =(40×175)=7,000

Desired gain on whole deal =10%

SP of all chairs =[1+10100]×7,000

=110100×7,000

=7,700

One-Fourth of all articles =14×40=10

C.P of 10 articles =10×175=1750

As these articles are sold at a loss of 8 %

SP of these articles =[18100] of 1750

=92100×1750

=1610

Selling price of remaining i .e 30 chairs = 7700- 1610 = 6090

∴ SP of each of the remaining chairs = 609030

 =₹203


Question 16

Sol :
S.P of two electronic gadgets = Rs 44,000 (each)

for first gadget 

SP= rs 44,000  , profit = 10% , C.P = ?

44,000=(1+10100) of (.P)CP=Rs(44,000×100110)=Rs40,000

For second gadget:

Sp=44,000, loss =12%,Cp=9 S. ρ=[11100] of CP44,000=[112100] of CPCP={[44,000×10088]={50,000.

Then, Total cost price =40,000+50,000=90,000

Total selling ρi(e=44,000+44,000=88,000

Loss =CP-SP=90,000-88,000=2,000

Loss percentage
 = Loss C.P×100=2,00099,000×10%=209=2.22%

Question 17

Sol :
Manufacturing price of a TV set =12,000

Shopkeeper Sold to a dealer at a profit of 20 %

Now s.p of de T.V set=[1+20100] of CP

Sp=120100×12,000=1.4,000

Dealer sold to a customer at 12.5 % profit

Now Dealer's s.p will become cost price

So, New selling price to Customer

=[1+12.5100] of CP=112.5100×14,000

= 16,200

So the customer pay 16200 for T .V SET 

Question 18

Sol :

(i) SP=450,  Loss=10 %

% Loss = Loss cp×10010=[1spcp]×1001spcp=110

SpC.P=1110=910

CP=450×109

CP=₹ 500


(ii) Sp=690, profit =15%Sp=[1+p100] of Cp690=[1+15100]×C.pCρ=690×100115C=Rs600



Question 19

Sol :

If S.P = 3920 , gain = 12 %

Sp=[1+p100] of cp

3920=[1+12100]×C.p

cp=3920×100112

C.P = 3,500

Now S.P= 4375

As SP>$CP

Gain =SP-CP
=4,375-3,500
=875

Gain percentage
=[Gaincp×100]%=[8753,500×100]%=25%

Question 20

Sol :
SP=1334 , Loss =8 %

Sp=[11100] of Cp

1334=[18100]×C.p

Cp=1334×10092cp=1450

Given profit =1212%=12.5%

Now Sp=[1+p100]×(c.p)

=[1+12.5100]×1450

Sp=112.5×1450100

SP=21631.25


Question 21

Sol :

Sp=252 Gain =5%SP=[1+P100]×CρCP=s.p×100100+P=252×100100+5Cp=25200105=240

SP=? if gain=35 %

SP=[1+p100] of CP

=[1+35100]×240

S1=135×240100

SP=2324

Question 22

Sol :
Let the selling price of a bag be ₹ x

profit = 12 % 

x=(1+12100)dfp

x=112100 of (pcp=100x112

To make 18 % profit

SP=[1+18100] of CP

=118100×100x112=59x56

According to given in formation, 59x56=x+39

59xx5639

3x56=3913

x=56×13

x=728=SP

 Cost price of bag=100×x112=100×728112 Cost price of bag =650

Question 23

Sol :

Let the S.P of Sweater be x, loos =5 %

x=[15160] of cpCp=100x95

To make 15 % profit

 S. p=[1+15100] of Cp=[1+15100]×100x95=115100×100x95=23x19

According to given information, 23x19=x+260

4x19=260x=65×19x=1235

Selling price of . Sweater =1,235


Question 24

Sol :

Let the selling price be "x" 
Loss =8 %

x=[18100] of cpcp=100x92

To make a profit of 12 % 

SP=[1+12100] ofcp=[112100×100x92]=28x23.

According to given information, 28x23=x+150

5x23=15030

Selling price, x=23×30=690

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