ML AGGARWAL CLASS 8 CHAPTER 7 Percentage Exercise 7.2
Exercise 7.2
Question 1
Sol :
(i) C.P 400 S.P = 468
S.P > c.p , profit = s.p-C.p =468−400=68
profit percentage = =( profit c⋅p×100)%
=(68400×100)%
=17
(ii) C.P = 13600 , S.P = 12104
As C.p > S. P Loss =c.p−s⋅p=13,600−12,10y=1496
loss percentage
=( Loss c.p×100)%=(149613600×100)%=11%
Question 2
Sol :
Given S⋅P=1636.25, gain =96.25
As Gain=S⋅p−Cp
⇒ C⋅P=S⋅p−Gain=1636.25−96.25=1540.
⇒ Gain percentage
=(Gainc⋅p×100)%=(96⋅251540×100)%=6.25%
Question 3
Sol :
Given
S.P = 770 LOSS = 110
As loss = c.p - s.p
c.p = loss + s.p
= 110 + 700
⇒ 880
Loss percentage
=( Loss c.p×100)%=(110880×100)%=12.5%
Question 4
Sol :
c.p of 1 dozen eggs =9.60
c.p of 25 dozen eggs =(25×9.6)=240
Total no of eggs =25×12=300 eggs
Out of 300 eggs, 30 eggs were broken
So the remaining no of eggs were 300 - 30 = 270 eggs
Given
S.P of each egg = Rs 1
S. of 270 eggs =270×1=270
As S⋅p>c.p, he always gets profit on given
So the gain percentage = (gainc⋅p×100)%
Gain = S.P - C.P
⇒ 270 - 240 = 30
Gain percentage = (30240×100)%
=12.5%
Question 5
C.P of an article
=20,000+1400 (repairs) =21,400
profit percentage =20 %
profit c.p ×100=20
Profit x×100=20×21,400
(SP−CP)=20×214
S.P-21,400=4280
Sp=21,400+4280sp=25680
Selling price of an article = 25,680
Question 6
Sol :C.P of bicycles includes
(i) 200 bicycles at 1200. per bicycle =(200×1200)=240000
(ii) 301- per bicycle on transportation =200×30=6000
(iii) 40001- on advertising =4000
Total cost price of bicycles =2,40,000+6000+4000
S.P of 200 bicycles =200×1350
As SP>CP, there is always a gain
So Gain =SP-CP
=2,70,000−2,50,000=20,000
=Gainc.p×100
=20,0002,50000×100
=8 %
Question 7
Sol :
Let S.P be ₹ x ,
then CP 90 % of x
=910x
Profit =s⋅p−c⋅p=x−9x10=x10
profit percentage =( Profit c. p×100)%=((x/10)(9×10)×100)%=1009%=11.11%
Question 8
Sol :
(i) CP of 4 note boots =₹35
then c.s of 1 note book =354=8.75
Sp of 5 note books =58
then s⋅p of 1 notebook =585=11.6%
As. SP>CP there is always a gain
Gain = SP-CP = 11.6 - 8.75
= 2.85
Gain percentage
=GainC⋅p×100=2.858.25×100=32.57%
(ii) Number of notebooks to be sold = total profit profit on one notebooks
=1712.85
=60
Question 9
Sol :
Cost price of 3 bananas = Rs 1
The c .p of 1 banana = Rs 13=0.33
S.p of 4 bananas = Rs 1
S.p of 4 bananas = Rs 1
Then S.P of 1 banana = Rs 14=0.25
As C.P>SP, These is always a loss.
Loss =C⋅p−s⋅p=13−14
=112
Loss percentage = Loss c.p×100%=(1/12)(1/3)×100%=1004%=25%
Question 10
Sol :
Given S.P of 5 pens = C.P of 7 pens
let cost price of one pen be x then
C.P of 7 pens = Rs 7x
It is given
S.P of 5 pens = c.p of 7 pens
S.P of 5 pens = rs 7x
S.P of one pen = 7x5
As SP>C.P there is a profit
profit =S⋅p−c⋅p=7x5−x=2x5
∴ Profit percentage = profit C⋅p×100%=(2x/5)x×100%=2005%=40%
Question 11
Sol :
(i) CP=2360, profit =8 %
As. Profit percentage = profit C.p×100
profit ×100=8×2360 profit =8×2360100S.P−C⋅p=188.8S⋅p=2360+188⋅8S⋅P=2548.8
(ii) CP=380 ; loss=7.5 %
Loss percentage = loss C.P ×100
Loss =7.5×380100
c⋅p−s.p=28.5s⋅p=380−28.5s⋅p=351.5
Question 12
Sol :
CP of dozen egg =18
then CP of 1 egg=1812=21.5
⇒Profit =50 %
SP−CPC.P×100=50
SP-CP=9
SP=18+9
SP=27
S.P of 1 egg =2712=22.25
Question 13
Sol :
Let the no of wrist watches are x
cost of x wrist watches Rs 60,000
C.P one third of wrist watches will worth 20,000
(i) As we know 13rd are sold at a 30% profit
S⋅p=[1+P100] of C.P=[1+30100]×20,000=130100×20,000=26,000
(ii) SP=[1+p100] of CP [∵
As 13rd are sold at 20 % gain]
=[1+20100]×20,000
=120100×20,000
=24,000
(iii) S⋅P=(1−l100) of c.p [Remaining are sold at a 5 % Less ]
=[1−5100]×20,000
=95100×20,000
=19,000
Total cost price = ₹ 60,000
Selling price =[26,000+24,000+19,000]=69000
As SP>CP these is always a profit
Gain=S⋅p−C⋅p=69,000−60,000=9,000
Gain percentage
==Gainc⋅p×100%=9,00069,000×100%=15%
Question 14
Sol :
C.P of a Laptop = 40,000
C.P of a mobile phone = 24,000
Total CP of whole Transaction =40,000+24,000
=64,000
As shopkeeper made a profit of 8 % on laptop
So. s⋅p=(1+p100) of c⋅p=[1+8100]×40,000=108100×40,000=43,200
Also, he made a loss of 12 % on mobile phone
SP=[1−l100] of C⋅P=[1−12100]×24,000=88100×24,000=21,120
Total S.P on whole Transaction =43,200+21,120
=64,320 .
As, SP>CP there is always a gain
Gain =S⋅p−c⋅p=64,320−64,000=320 Gain percentage =GainCip×100
=0.5 %
Question 15
Sol :
C.P of 40 chairs =(40×175)=7,000
Desired gain on whole deal =10%
SP of all chairs =[1+10100]×7,000
=110100×7,000
=7,700
One-Fourth of all articles =14×40=10
C.P of 10 articles =10×175=1750
As these articles are sold at a loss of 8 %
SP of these articles =[1−8100] of 1750
=92100×1750
=1610
Selling price of remaining i .e 30 chairs = 7700- 1610 = 6090
∴ SP of each of the remaining chairs = 609030
=₹203
Question 16
Sol :
S.P of two electronic gadgets = Rs 44,000 (each)
for first gadget
SP= rs 44,000 , profit = 10% , C.P = ?
44,000=(1+10100) of (.P)C⋅P=Rs(44,000×100110)=Rs40,000
For second gadget:
S⋅p=44,000, loss =12%,C⋅p=9 S. ρ=[1−1100] of C⋅P44,000=[1−12100] of C⋅PC⋅P={[44,000×10088]={50,000.
Then, Total cost price =40,000+50,000=90,000
Total selling ρi(e=44,000+44,000=88,000
Loss =CP-SP=90,000-88,000=2,000
Loss percentage
= Loss C.P×100=2,00099,000×10%=209=2.22%
Question 17
Sol :
Manufacturing price of a TV set =12,000
Shopkeeper Sold to a dealer at a profit of 20 %
Now s.p of de T.V set=[1+20100] of CP
S⋅p=120100×12,000=1.4,000
Dealer sold to a customer at 12.5 % profit
Now Dealer's s.p will become cost price
So, New selling price to Customer
=[1+12.5100] of CP=112.5100×14,000
= 16,200
So the customer pay 16200 for T .V SET
Question 18
Sol :
(i) SP=450, Loss=10 %
% Loss = Loss c⋅p×10010=[1−s⋅pc⋅p]×1001−s⋅pc⋅p=110
S⋅pC.P=1−110=910
CP=450×109
CP=₹ 500
(ii) Sp=690, profit =15%S⋅p=[1+p100] of C⋅p690=[1+15100]×C.pC⋅ρ=690×100115C⋅=Rs600
Question 19
Sol :
If S.P = 3920 , gain = 12 %
S⋅p=[1+p100] of c⋅p
3920=[1+12100]×C.p
c⋅p=3920×100112
C.P = 3,500
Now S.P= 4375
As SP>$CP
Gain =SP-CP
=4,375-3,500
=875
Gain percentage
=[Gainc⋅p×100]%=[8753,500×100]%=25%
Question 20
Sol :
SP=1334 , Loss =8 %
S⋅p=[1−1100] of C⋅p
1334=[1−8100]×C.p
C⋅p=1334×10092c⋅p=1450
Given profit =1212%=12.5%
Now S⋅p=[1+p100]×(c.p)
=[1+12.5100]×1450
S⋅p=112.5×1450100
SP=21631.25
Question 21
Sol :
S⋅p=252⋅ Gain =5%S⋅P=[1+P100]×C⋅ρC⋅P=s.p×100100+P=252×100100+5C⋅p=25200105=240
SP=? if gain=35 %
SP=[1+p100] of CP
=[1+35100]×240
S⋅1=135×240100
SP=2324
Question 22
Sol :
Let the selling price of a bag be ₹ x
profit = 12 %
x=(1+12100)df⋅p
x=112100 of (⋅pc⋅p=100x112
To make 18 % profit
SP=[1+18100] of CP
=118100×100x112=59x56
According to given in formation, 59x56=x+39
59x−x56−39
3x56=3913
x=56×13
x=728=SP
Cost price of bag=100×x112=100×728112 Cost price of bag =₹650
Question 23
Sol :
Let the S.P of Sweater be x, loos =5 %
x=[1−5160] of c⋅pC⋅p=100x95
To make 15 % profit
S. p=[1+15100] of C⋅p=[1+15100]×100x95=115100×100x95=23x19
According to given information, 23x19=x+260
4x19=260x=65×19x=1235
∴ Selling price of . Sweater =1,235
Question 24
Sol :
Let the selling price be "x"
Loss =8 %
x=[1−8100] of c⋅pc⋅p=100x92
To make a profit of 12 %
S⋅P=[1+12100] ofc⋅p=[112100×100x92]=28x23.
According to given information, 28x23=x+150
5x23=15030
Selling price, x=23×30=₹690
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