ML AGGARWAL CLASS 8 CHAPTER 8 Simple and Compound Interest Exercise 8.1

 Exercise 8.1

Question 1

Sol :

Principal (P)=4000


Rate of Interest (R)=7.5%


Time (T)=3years and 3 months


1month=112 year 3 months =312 year =14 year  Time =314 years =134 years 


Simple interest (I)=PTR100


Simple interest (I) =975


Amount = principal + interest 

= 4000 + 975 


Amount = 4975 




Question 2

Sol :
Given 
simple interest (I) = 170 .10 

Time (T) = 2 year and 3 month 

(T) 2312=214=94 years

Rate (R)= 6% 

P=I×100R×T=170.10×1006×94.

Principal == p = 1260 


Question 3

Sol :
Given 

principal = 800

simple interest (I) = 130 

Time = 2 year and 6 months 

Time = 2612=212=52 years

R=I×100P×T=130×100800×52R=6.5%

hence , the required rate of interest = 6.5% 


Question 4

Sol :

Given
principal (p) = 3.3 lakhs
p = 330000

rate (R) 6.5 % 

 Simple Interest =75075/ Time (T)=I×100P×R=75075×100330000×6.5T=3.5 years 

Hence , the required time = 3 years and 6 months 


Question 5

Sol :

(i) simple interest (I) = 2356.25 

Time (T)=2.12 yeers T=52 years (R)=714%R=2941.P=I×100T×R=2356.25×10052×294P=13,000

Hence , the required principal is Rs 13000 


(ii)  Given 

rate (R) = 4 %

 Time (T)=3 years and 3 month s=3312=314=134T=134 years 

Final Amount =113001

Final Amount = Principal (D)+Simple interest (I)

11300=P+PTR100

11300=P(1+TR100)

11300=P(1+134×4100)

11300=P(113100)

P=11300×100113

P=10,000

Hence , the required principal is 10 ,000


Question 6

Sol :

Given    
Interest rate (R) = 1313=403 %
Final amount = 3 ×principal (p) 

P+I=3PI=3pPI=2PPTR100=2P(I=PTR100)T=200RT=200403

Times = T = 15 years 

Hence , the required time to triple itself for given 

Interest rate is 15 years.


Question 7

Sol :

Given  

principal (P1)=4050
Final Amount =4576.501

 Prinupal + Simple Interest =4576.504050+I1=4576.50I1=526.50 Time =2 years. 

I1=P1T1R100

526.50=4050×2×R100

R=6.5% per annum

Now we have to calculate simple interest for 1 lakh for 3 years at a rate of 65 % per annum 

I2=P2T2R100I2=1,001000×3×6.5100I2=19500

 Total Amount =P2+I2=1,00,000+19,500=1,19,500

∴ Hence , the 1 lakh will amount Rs 1,19,500 for 3 years

Question 8

Sol :
Let the money invested to be Rs p 

Given

Prinupel P1=P

Rate R1=7.51

Time T1=2 years

Let Interest =I1

Principal P2=9600

Rate R2=101.

Time =3 years and 6 months.

. Time Tz=312=72 years

let Simple Interest =I2

I1=2×I2

P1T1R1100=2×P2T2R2100

P×2×7.5100=2×9600×72×10100

P = Rs 4,4800 

= Rs 44,800

Hence the required sum of money is Rs 44,800

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