ML AGGARWAL CLASS 8 CHAPTER 8 Simple and Compound Interest Exercise 8.1
Exercise 8.1
Question 1
Sol :
Principal (P)=4000
Rate of Interest (R)=7.5%
Time (T)=3years and 3 months
1month=112 year 3 months =312 year =14 year ∴ Time =3⋅14 years =134 years
Simple interest (I)=PTR100
Simple interest (I) =975
Amount = principal + interest
= 4000 + 975
Amount = 4975
Question 2
Sol :
Given
Given
simple interest (I) = 170 .10
Time (T) = 2 year and 3 month
(T) 2⋅312=2⋅14=94 years
Rate (R)= 6%
P=I×100R×T=170.10×1006×94.
Principal == p = 1260
Question 3
Sol :
Given
principal = 800
simple interest (I) = 130
Time = 2 year and 6 months
Time = 2⋅612=2⋅12=52 years
R=I×100P×T=130×100800×52R=6.5%
hence , the required rate of interest = 6.5%
Question 4
Sol :
Given
principal (p) = 3.3 lakhsp = 330000
rate (R) 6.5 %
Simple Interest =75075/− Time (T)=I×100P×R=75075×100330000×6.5T=3.5 years
Hence , the required time = 3 years and 6 months
Question 5
Sol :
(i) simple interest (I) = 2356.25
Time (T)=2.12 yeers T=52 years (R)=7⋅14%R=294−1.P=I×100T×R=2356.25×10052×294P=13,000
Hence , the required principal is Rs 13000
(ii) Given
rate (R) = 4 %
Time (T)=3 years and 3 month s=3⋅312=3⋅14=134T=134 years
Final Amount =113001−
Final Amount = Principal (D)+Simple interest (I)
11300=P+PTR100
11300=P(1+TR100)
11300=P(1+134×4100)
11300=P(113100)
P=11300×100113
P=10,000
Hence , the required principal is 10 ,000
Question 6
Sol :
Given
Interest rate (R) = 1313=403 %Final amount = 3 ×principal (p)
P+I=3PI=3p−PI=2PPTR100=2P(∵I=PTR100)T=200RT=200403
Times = T = 15 years
Hence , the required time to triple itself for given
Interest rate is 15 years.
Question 7
Sol :
Given
Final Amount =4576.501
Prinupal + Simple Interest =4576.504050+I1=4576.50I1=526.50 Time =2 years.
I1=P1T1R100
526.50=4050×2×R100
R=6.5% per annum
Now we have to calculate simple interest for 1 lakh for 3 years at a rate of 65 % per annum
I2=P2T2R100I2=1,001000×3×6.5100I2=19500
Total Amount =P2+I2=1,00,000+19,500=1,19,500
∴ Hence , the 1 lakh will amount Rs 1,19,500 for 3 years
Question 8
Sol :
Let the money invested to be Rs p
Let the money invested to be Rs p
Given
Prinupel P1=P
Rate R1=7.5−1
Time T1=2 years
Let Interest =I1
Principal P2=₹9600
Rate R2=10−1.
Time =3 years and 6 months.
. Time Tz=3⋅12=72 years
let Simple Interest =I2
∴I1=2×I2
P1T1R1100=2×P2T2R2100
P×2×7.5100=2×9600×72×10100
P = Rs 4,4800
= Rs 44,800
Hence the required sum of money is Rs 44,800
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