ML AGGARWAL CLASS 8 CHAPTER 9 Direct and Inverse Variation Exercise 9.1

 Excercise: 9.1

Question 1 

Sol :
(i) 515=13,824=13,1236=13,1560=14,1872=14,20100=15

Here xy=515=824=1236=131560=1872=1420100=15

ஃ x and y are not proportional.


(ii) 39=13,515=13,721=13,927=13,1030=13.

Here xy=39=515=721=9271030=13= Constant

ஃ x and y are not proportional

Question 2

Sol :
(i) xy=345=5y2=x390=x4120=x5y5=115= constant

5y2=115x390=115x4120=115y2=15×5x3=90/15x4=120/15y2=75x3=6x4=8


10y5115

y5=15×10=150

x3=6,x48,y2=75



(ii) x4=47=8y2=x321=2044=28y5= constant

y7=8y2y7=x12147=20y44y2=7×8x3=4×137y4=204y2=7×84x3=4×3y4=5×7y2=14x3=12y4=35

47=2845y5=7×284y5=49

y2=14,x3=12,y4=35,y5=47

Question 3

Sol :
Let the cost of 5.8 mts of cloth be Rs x

Cost of 8 mts of cloth cost Rs 250 

so it is a case of direct variation 

i .e 8250=5.8x

x=250×5.88=25×588

x=181.25

∴ Cost of 5.8 mts of cloth Rs 181.25

Question 4

Sol :
Labourer earns Rs 672 per week i . e 7 days 

Labourer in 7 days he earns Rs 672

in 1 day he earn  Rs 6727

= Rs 96

Now in 18 days he earns Rs 96 × 18

= Rs 1458

Question 5

Sol :
Given 175 dollars cost Rs 7,350

how many dollars cost Rs  24,24

Let the no of dollar be x

x175=240247350\

x=572

572 dollars cost Rs 24,024




Question 6

Sol :
Let the number of kilometers travelled be 'x' 

car travels 675 km in 4.5 litres of petrol 

x km in 26 .4 litres of petrol

i.e x675=26445

x=26.4×67.54.5

x=396 km

∴  Number of kilometers travelled is 396 km

Question 7

Sol :
Let the number of sheets of cardboard be x

thickness of 12 cardboard sheets is 45 mm

Thickness of x cardboard sheets is 90 cm i .e 900mm

i .e x12=90045

x=900×1245x=240

∴ Number of sheets of cardboard are 240

Question 8

Sol :
Mast of shop model is 6cm 

Mast of achol shop is 9 m = 900cm 

length of achol ship is 33m = 3300cm

Let length of model ship is x

6900=x3300x=6×33xyx=22 cm

model length of ship = 22cm


Question 9

Sol :
Mass of aluminium rod varies directly with length

M ×  L

Mass of 16 cm long rod has 192 g

mals of x cm longrod has losg

 x=105×16192

i.e x16=105192

x=8.75 cm

105g mass has length of rod is 8.75cm

Question 10

Sol :
Given Map scale 1cm=20 km

Anita Measures a distance from village A to

Village B is 3.5 cm
Actual distance between them is 3.5×20

=35×2=70 km

Question 11

Sol :
(i) Height of water tank is 23m 74cm i.e 2375 cm

length of shadow is 20m i .e 2000cm

if height of tree is 9 m 50 cm i .e 950 cm

length of shadow is 'x' = ?

i.e
 x2000=9502335x=950×20002375x=800 cmi.e8m

Length of Shadow is 8 m


(ii) if length of shadow is 12m = 1200 cm

Height of free = ? Let = 'x' 

x2375=12002000

x=1200×23752000

x=1425 cm i.e 14 m 2 cm

Heigth of free is 14 m25 cm hight



Question 12

Sol :
Earning of 5 men= Earing of 7 women

Earning of 1 man=earingof\frac{7}{5}$ women

Earing of 10 man= earning of (78×10) women

= earing of 14 women

Earning of 10 men and 13 women = earning of (14 + 13 ) women

= earning of 27 women

Let 10 men and 13 women i .e 27 women earn ₹ x in a day 

Note that more women will earn more per day 

hence , 10 men and 13 women will earn Rs 2025 in a day 

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