ML AGGARWAL CLASS 8 CHAPTER 9 Direct and Inverse Variation Exercise 9.3
Exercise 9.3
Question 1
Sol :
Farmer can reap a field in 10 days
his wife can reap it in 8 days
Farmer one day work i,e reap a field is 110.
His wife one day work is 18
Fasmer and wife can completed if Key work together
i.e 110+18
=4+540=940
∴ Both together can complete in 409 days
Question 2
Sol :
Since A can complete 15k of work in 2 days
∴ A's one day work =12 of $\frac{1}{5}=\frac{1}{2} \times \frac{1}
{5}=\frac{1}{10}$
Since B Can Complete 23nd of work in 8 days
∴B′s is one day wak =23 of 18=23×184=112
One days work of A and B together = 110+112
6+560=1160.
∴ A and B working together can complete the work in 6011 days
Question 3
Sol :
'A' tap can fill a tank in 20 minutes
A tap one minutes can fill 120th of tank
"B" Tap can fill a tank in 12 mint
In one minute, Tap B can fill 112th of Tank
If both taps were opened then
In one minutes, TapA and B can fill =120+112
=3+560
=860
∴ Both A and B will fill the tank in 608 minutes
Question 4
Sol :
A can do a work in 6 days
B Can do a work in 8 days
A's one day work =16
B's one day work =18
One days work of A and B Together = 16+18
4+324=724
∴ 2 days work of A and B together = 2×724=712
∴ Remaining work = 1−712=512
∴ The no. OF days taken by A to finish the remaining work
= work to be done A's one day work =5/121/6=5122×6=52 day
Hence , A will complete the remaining work in 52 days
Question 5
Sol :
A can do a piece of work in 40 days
A's one day work = 140
He works for 8 days , he complete 8×140=15th wok
Remaining work = 1−15=45
B finisher remaining work in 16 days
i.e B finisher 45th wok in 16×54 day
=20 days
A and B Can completed in =120+140=2+140=340.
∴ It takes 402 days if they do together.
Question 6
Sol :
A and B separately do work in 10 and 15 days
A's one day work =110 days
B's one day work =115 days
A and B one's day wak =110+115=3+230=530=16.
A completed the remaining work in 5 days
i .e 12 of the work had completed
Remaining half work had completed by A and B together
i.e 12×6=3 days
Question 7
Sol :
1 women or 5 girks take 17 days to complete a piece
of work
Since 3 women's work = 5 girls work
1 woman's work =53 girl's work
:7 women work =53×7 i.e 353 gins work
∴ 7women and 11 girls work =353+11 i .e 683 girls work
Since 5 girls can do work in 17 days
∴ 1 girl can do work in 5×17 i .r 85 days
683 girls can do the work in 8568/3 days
83×368
=154 days
Hence 7 women and 11 girls working together will complete
the work in 154 days
Question 8
Sol :
A's one day work =110
B's one day wok =115.
So they divide money in the ratio 110:115
i.e 110×30:115×30 i.e 3:sum=3+2=5
A's share = 35×3500=3×700=2100
B's share : 25×3,500=2×700=1400
Question 9
Sol :
A's one day work =12
B's one day work r16
C's one day work =13.
A, B , C one's days work together =12+13+16
3+2+16=66=1
A,B,C completed their work by working together in 1 day
So they divide the money in the ratio 12:16:13
i.e
12×6:16×6:13×6=3:1:2
Sum of these terms = 3+1+2+6
A's share =38×960=3×160=480
B's share =16×960=1×160=160
C's share =26×960=2×160=320
Question 10
Sol :
A and B , c together do a piece of work in 15 days
one's days work of A,B and C together is 115
B's one day work =130
C's one day work =140.
A's one day work =115−{130+140}
115−{4+3120}
115−7120
=8−7120
A's one day work = 1120
∴ A alone do the work in 120 days
Question 11
Sol :
A's one day +B's one day + C's one day =524
A's one day +C's one day=18.
B's one day work
=524−18=5−324=224=112
∴ B alone can plough field in 12 days
Question 12
Sol :
A's one day work +B' s one ofay work =110
B's one day work +C's is one day work =115
C's one day work +A's
As one day work =112
2 (A's one day work + B's one days work +C's one day work)
=110+115+112
=6+4+560=1560−14
A's one day work + B's one day work + C's one day work = 14×12
=18
$\therefore A, B, C together can complete in 8 days
A's one day work = 18−115
=15−8120=7120
∴ A alone takes 1207 days
B's one day work =18−112
= 3−224=124
B alone takes 24 days
C's one day work =18−110
=5−440=140
C alone takes 40 days
Question 13
Sol :
Pipe fill a tank in 12 hour
In one hour , pipe fills 112 of the tank
A waste pipe is left opened and filled in 16 hour
In one hour , it fills 116 of tank
∴ portion of tank emptied by the waste pipe
in one hour = 112−116
=4−348
=148
∴ Waste pipe takes 48 hours to empty the tank
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