ML AGGARWAL CLASS 8 CHAPTER 11 Factorisation Exercise 11.2

 Exercise 11.2

Solution 1

Sol :
(i)
x2+xyxyx(x+y)1(x+y)(x+y)(x1)

(ii)
y2yz5y+5zy(yz)5(yz)(yz)(y5)


Solution 2

Sol :
(i) 
5xy+7y5y27x5xy5y2+7y7x.5xy5y27x+7y5y(xy)7(xy)(xy)(5y7)


(ii) 5p28pq10p+16q

5p210p8pq+16q

5p(p-2)-8q(p-2)

(p-2)(5p-8q)



Solution 3

Sol :
(i) 
a2bab2+3a3bab(ab)+3(ab)(ab)(ab+3)


(ii)
x33x2+x3=x2(x3)+1(x3)(x3)(x2+1)



Solution 4

Sol :
(i) 
6xy23xy10y+53xy(2y1)5(2y1)(2y1)(3xy5)


(ii) 3ax-6ay-8by+4 bx
3a(x-2 y)+2b(-2y+x)
3a(x2y)+2b(x2y)

(x2y)(3a+2b)



Solution 5

Sol :
(i) x2+xy(1+y)+y3\

x2+xy+xy2+y3

x(x+y)+y2(x+y)

(x+y)(x+y2)


(ii) y2xy(1x)x3

y2xy+x2yx3

y(yx)+x2(yx)

(yx)+(y+x2)


Solution 6

Sol :
(i) ab2+(a1)b1

ab2+abb1

ab(b+1)-(b+1)

(b+1)(a b-1)


(ii) 2a-4b-xa+2bx

=2(a-2b)-x(a-2b)

=(a-2b)(2-x)


Solution 7

Sol :
(i) 5ph-10qk+2rph-4q rk
=5(p h-2 q k)+2 r(p h-2 q k)
=(ph2qk)(5+2r)


(ii) x2x(a+2b)+2ab

=x2xa2bx+2ab

=x(x-a)-2 b(x-a)

=(x-a)(x-2 b)

Solution 8

Sol :
(i) ab(x2+y2)xy(a2+b2)

=abx2+aby2xya2xyb2

=a x(b x-a y)+b y(a y-b x)

=a x(b x-a y)-b y(b x-a y)

=(b x-a y)(a x-b y)


(ii) (ax+by)2+(bxay)2

=a2x2+b2y2+2axby+b2x2+a2y22bx.ay

=x2(a2+b2)+y2(a2+b2)

=(a2+b2)(x2+y2)

Solution 9

 Sol :
(i)a3+ab(12a)2b2

=a3+ab2ab2b2

=a(a2+b)2b(a2+b)

= (a2+b)(a2b)

 
(ii) 3x2y3xy+12x12

=3xy(x-1)+12(x-1)

=(x-1)(3 x y+12)

=(x-1)3(x y+4)

=3(x1)(xy+4)

Solution 10

Sol :
(i) a2b+ab2abcb2c+axy+bxy

=(a2b+ab2)(abc+b2c)+(axy+bxy)

=a b(a+b)-b c(a+b)+x y(a+b)

=(a+b)(a b-b c+x y)

 
(ii) ax2bx2+ay2by2+az2bz2

=x2(ab)+y2(ab)+x2(ab)

=(ab)(x2+y2+z2)

Solution 11

Sol :
(i) x1(x1)2+axa

=1(x1)(x1)2+a(x1)

=(x1)(1(x1)+a)

=(x-1)(1-x+1+a)

=(x-1)(2-x+a)


(ii) ax+a2x+aby+by(ax+by)2

=ax+by+a2x+aby(ax+by)2

=1(ax+by)+a(ax+by)(ax+by)2

=(a+b y)(1+a-a x-b y)

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